(y^2+2xy)-(x^2)dx=0

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Solution for (y^2+2xy)-(x^2)dx=0 equation:


Simplifying
(y2 + 2xy) + -1(x2) * dx = 0

Reorder the terms:
(2xy + y2) + -1(x2) * dx = 0

Remove parenthesis around (2xy + y2)
2xy + y2 + -1(x2) * dx = 0

Multiply x2 * dx
2xy + y2 + -1dx3 = 0

Reorder the terms:
-1dx3 + 2xy + y2 = 0

Solving
-1dx3 + 2xy + y2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2xy' to each side of the equation.
-1dx3 + 2xy + -2xy + y2 = 0 + -2xy

Combine like terms: 2xy + -2xy = 0
-1dx3 + 0 + y2 = 0 + -2xy
-1dx3 + y2 = 0 + -2xy
Remove the zero:
-1dx3 + y2 = -2xy

Add '-1y2' to each side of the equation.
-1dx3 + y2 + -1y2 = -2xy + -1y2

Combine like terms: y2 + -1y2 = 0
-1dx3 + 0 = -2xy + -1y2
-1dx3 = -2xy + -1y2

Divide each side by '-1x3'.
d = 2x-2y + x-3y2

Simplifying
d = 2x-2y + x-3y2

Reorder the terms:
d = x-3y2 + 2x-2y

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